Integrand size = 26, antiderivative size = 71 \[ \int \frac {A+B x}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {B}{3 b^2 \left (a^2+2 a b x+b^2 x^2\right )^{3/2}}-\frac {A b-a B}{4 b^2 (a+b x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \]
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Time = 0.01 (sec) , antiderivative size = 71, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {654, 621} \[ \int \frac {A+B x}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {A b-a B}{4 b^2 (a+b x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2}}-\frac {B}{3 b^2 \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \]
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Rule 621
Rule 654
Rubi steps \begin{align*} \text {integral}& = -\frac {B}{3 b^2 \left (a^2+2 a b x+b^2 x^2\right )^{3/2}}+\frac {\left (2 A b^2-2 a b B\right ) \int \frac {1}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx}{2 b^2} \\ & = -\frac {B}{3 b^2 \left (a^2+2 a b x+b^2 x^2\right )^{3/2}}-\frac {A b-a B}{4 b^2 (a+b x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(345\) vs. \(2(71)=142\).
Time = 0.97 (sec) , antiderivative size = 345, normalized size of antiderivative = 4.86 \[ \int \frac {A+B x}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {x \left (-3 \sqrt {a^2} A b^7 x^7-3 a^3 b^4 x^4 \sqrt {(a+b x)^2} (A+B x)+3 a^2 b^5 x^5 \sqrt {(a+b x)^2} (A+B x)+6 a^7 (2 A+B x) \left (\sqrt {a^2}-\sqrt {(a+b x)^2}\right )+3 a b^6 x^6 \left (\sqrt {a^2} B x-A \sqrt {(a+b x)^2}\right )+a^5 b^2 x^2 \left (12 \sqrt {a^2} A-6 A \sqrt {(a+b x)^2}+B x \left (\sqrt {a^2}-3 \sqrt {(a+b x)^2}\right )\right )+3 a^4 b^3 x^3 \left (B x \sqrt {(a+b x)^2}+A \left (\sqrt {a^2}+\sqrt {(a+b x)^2}\right )\right )+2 a^6 b x \left (9 \sqrt {a^2} A-3 A \sqrt {(a+b x)^2}+B x \left (2 \sqrt {a^2}+\sqrt {(a+b x)^2}\right )\right )\right )}{12 a^8 (a+b x)^3 \left (a^2+a b x-\sqrt {a^2} \sqrt {(a+b x)^2}\right )} \]
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Time = 0.38 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.46
method | result | size |
gosper | \(-\frac {\left (b x +a \right ) \left (4 B b x +3 A b +B a \right )}{12 b^{2} \left (\left (b x +a \right )^{2}\right )^{\frac {5}{2}}}\) | \(33\) |
default | \(-\frac {\left (b x +a \right ) \left (4 B b x +3 A b +B a \right )}{12 b^{2} \left (\left (b x +a \right )^{2}\right )^{\frac {5}{2}}}\) | \(33\) |
risch | \(\frac {\sqrt {\left (b x +a \right )^{2}}\, \left (-\frac {B x}{3 b}-\frac {3 A b +B a}{12 b^{2}}\right )}{\left (b x +a \right )^{5}}\) | \(39\) |
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Time = 0.37 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.86 \[ \int \frac {A+B x}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {4 \, B b x + B a + 3 \, A b}{12 \, {\left (b^{6} x^{4} + 4 \, a b^{5} x^{3} + 6 \, a^{2} b^{4} x^{2} + 4 \, a^{3} b^{3} x + a^{4} b^{2}\right )}} \]
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\[ \int \frac {A+B x}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=\int \frac {A + B x}{\left (\left (a + b x\right )^{2}\right )^{\frac {5}{2}}}\, dx \]
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Time = 0.20 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.79 \[ \int \frac {A+B x}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {B}{3 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {3}{2}} b^{2}} + \frac {B a}{4 \, b^{6} {\left (x + \frac {a}{b}\right )}^{4}} - \frac {A}{4 \, b^{5} {\left (x + \frac {a}{b}\right )}^{4}} \]
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Time = 0.28 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.46 \[ \int \frac {A+B x}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {4 \, B b x + B a + 3 \, A b}{12 \, {\left (b x + a\right )}^{4} b^{2} \mathrm {sgn}\left (b x + a\right )} \]
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Time = 10.03 (sec) , antiderivative size = 43, normalized size of antiderivative = 0.61 \[ \int \frac {A+B x}{\left (a^2+2 a b x+b^2 x^2\right )^{5/2}} \, dx=-\frac {\sqrt {a^2+2\,a\,b\,x+b^2\,x^2}\,\left (3\,A\,b+B\,a+4\,B\,b\,x\right )}{12\,b^2\,{\left (a+b\,x\right )}^5} \]
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